If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5p^2-10p-120=0
a = 5; b = -10; c = -120;
Δ = b2-4ac
Δ = -102-4·5·(-120)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-50}{2*5}=\frac{-40}{10} =-4 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+50}{2*5}=\frac{60}{10} =6 $
| -7+6v=7+4v | | (5z-2)(4-z)=0 | | 3(n-5)+5=37+n-12 | | 4(n+25)=2n+40 | | 3p-5=63 | | 4/n=48/12 | | 15/(p+2)=20/8 | | x+9=6/2 | | 6(4x+5)=-114 | | 35+x+12=90 | | 8p-4-5p=6-2p | | 13x+3=69.6 | | 5m+4-3=19 | | 7x-22=0 | | 4p-7=6+4p | | 2x+3.2=9.6 | | -6m-10=9+3m+8 | | 6=8+n/7 | | 24n=+8 | | -18=1/6y | | -5(5-3x)=-70 | | 4-4z=-4z+6 | | a3-8=2 | | 96+t-32=14t+12 | | 5+5/6x=1/3x-1 | | x+28+4x-3=7x-15 | | 9(d+5)=4(d-4)+5d | | 2+4a=-18 | | 7x-4=(-25) | | m=2(2)+-7 | | 5d-15=20 | | -3(6x+1)=-57 |